← Foundation MCQs ⚛️ Physics MCQs 100 questions • Q1–50 Moderate • Q51–100 Very Difficult • 30 Clinical/Scenario-based • Tap “Answer” for explanation.
Moderate
Q1. A 2 kg body accelerates at 3 m/s². What net force acts on it? A. 6 N B. 1.5 N C. 5 N D. 9 N Answer Correct: A. 6 N Explanation: F = ma = 2 × 3 = 6 N.
Key Concept / Clinical Relevance: Newton’s second law
Moderate
Q2. A car increases its speed from 10 to 20 m/s in 5 s. Its average acceleration is: A. 1 m/s² B. 2 m/s² C. 5 m/s² D. 6 m/s² Answer Correct: B. 2 m/s² Explanation: a = Δv/Δt = 10/5 = 2 m/s².
Key Concept / Clinical Relevance: Kinematics
Moderate
Q3. Which quantity is conserved in an isolated collision even when kinetic energy is not? A. Velocity B. Force C. Momentum D. Acceleration Answer Correct: C. Momentum Explanation: Total linear momentum is conserved in every isolated collision.
Key Concept / Clinical Relevance: Conservation of momentum
Moderate
Q4. A 10 N force moves an object 4 m in its own direction. Work done is: A. 2.5 J B. 14 J C. 400 J D. 40 J Answer Correct: D. 40 J Explanation: W = Fs cos 0° = 10 × 4 = 40 J.
Key Concept / Clinical Relevance: Work
Moderate
Q5. If the speed of a body doubles, its kinetic energy becomes: A. 4 times B. 2 times C. 8 times D. unchanged Answer Correct: A. 4 times Explanation: Kinetic energy is proportional to v².
Key Concept / Clinical Relevance: Kinetic energy
Moderate
Q6. For uniform circular motion, centripetal acceleration is directed: A. Tangentially B. Toward centre C. Away from centre D. Along velocity Answer Correct: B. Toward centre Explanation: Centripetal acceleration v²/r always points toward the centre.
Key Concept / Clinical Relevance: Circular motion
Moderate
Q7. The pressure at depth h in a static liquid of density ρ, above atmospheric contribution, is: A. ρg/h B. gh/ρ C. ρgh D. ρh/g Answer Correct: C. ρgh Explanation: Hydrostatic gauge pressure is ρgh.
Key Concept / Clinical Relevance: Fluid statics
Moderate Clinical / Scenario
Q8. A patient receives IV fluid from a bag raised higher above the vein. Why does flow tend to increase? A. Fluid density falls B. Viscosity becomes zero C. Venous pressure must rise D. Hydrostatic pressure head increases Answer Correct: D. Hydrostatic pressure head increases Explanation: Raising the bag increases ΔP = ρgh and therefore the driving pressure for flow.
Key Concept / Clinical Relevance: Hydrostatic pressure in IV infusion
Moderate
Q9. According to Poiseuille’s law, flow through a cylindrical tube is most sensitive to changes in: A. Radius B. Length C. Pressure only D. Density Answer Correct: A. Radius Explanation: Laminar flow varies with the fourth power of radius.
Key Concept / Clinical Relevance: Poiseuille flow
Moderate
Q10. Reynolds number is most useful for estimating the tendency toward: A. Radioactive decay B. Turbulent flow C. Refraction D. Heat radiation Answer Correct: B. Turbulent flow Explanation: Higher Reynolds number increases the likelihood of turbulence.
Key Concept / Clinical Relevance: Fluid dynamics
Moderate
Q11. Surface tension tends to make a liquid surface: A. Maximise area B. Increase volume indefinitely C. Minimise area D. Eliminate pressure Answer Correct: C. Minimise area Explanation: Surface tension minimizes surface area.
Key Concept / Clinical Relevance: Surface tension
Moderate
Q12. Young’s modulus is the ratio of: A. Strain/stress B. Force/area only C. Energy/time D. Stress/strain Answer Correct: D. Stress/strain Explanation: Within the elastic limit, Young’s modulus = longitudinal stress/strain.
Key Concept / Clinical Relevance: Elasticity
Moderate
Q13. Heat transfer through direct molecular interaction in a stationary solid is mainly: A. Conduction B. Convection C. Radiation D. Evaporation Answer Correct: A. Conduction Explanation: Conduction transfers thermal energy through microscopic interactions without bulk flow.
Key Concept / Clinical Relevance: Heat transfer
Moderate Clinical / Scenario
Q14. A febrile patient loses heat when sweat evaporates from skin. The principal physical mechanism is: A. Conduction into skin B. Latent heat of vaporisation C. Nuclear radiation D. Compression heating Answer Correct: B. Latent heat of vaporisation Explanation: Evaporation requires latent heat, which is taken from the body and cools it.
Key Concept / Clinical Relevance: Thermoregulation
Moderate
Q15. At constant temperature, Boyle’s law states that for a fixed amount of gas: A. P ∝ V B. P/T = constant C. PV = constant D. V/T = constant Answer Correct: C. PV = constant Explanation: For an isothermal ideal gas process, pressure is inversely proportional to volume.
Key Concept / Clinical Relevance: Gas laws
Moderate
Q16. The first law of thermodynamics is fundamentally a statement of conservation of: A. Charge B. Momentum C. Mass only D. Energy Answer Correct: D. Energy Explanation: Energy added as heat is partitioned into change in internal energy and work.
Key Concept / Clinical Relevance: Thermodynamics
Moderate
Q17. Entropy of an isolated system undergoing a spontaneous irreversible process generally: A. Increases B. Decreases C. Remains exactly zero D. Becomes negative Answer Correct: A. Increases Explanation: The second law requires total entropy not to decrease for an isolated system.
Key Concept / Clinical Relevance: Entropy
Moderate Clinical / Scenario
Q18. During quiet inspiration, alveolar pressure briefly becomes slightly subatmospheric because: A. Lung volume decreases B. Thoracic volume increases C. Airway resistance becomes zero D. Gas temperature doubles Answer Correct: B. Thoracic volume increases Explanation: Expansion increases gas volume and lowers alveolar pressure, drawing air inward.
Key Concept / Clinical Relevance: Pressure–volume relationship in ventilation
Moderate
Q19. Coulomb force between two point charges varies with separation r as: A. r B. 1/r C. 1/r² D. r² Answer Correct: C. 1/r² Explanation: Coulomb’s law gives F ∝ 1/r².
Key Concept / Clinical Relevance: Electrostatics
Moderate
Q20. Electric potential difference is energy transferred per unit: A. Current B. Resistance C. Power D. Charge Answer Correct: D. Charge Explanation: Voltage is work or energy per coulomb.
Key Concept / Clinical Relevance: Electric potential
Moderate
Q21. Two identical resistors R connected in parallel have equivalent resistance: A. R/2 B. 2R C. R D. R² Answer Correct: A. R/2 Explanation: 1/Req = 1/R + 1/R = 2/R.
Key Concept / Clinical Relevance: Parallel circuits
Moderate
Q22. A 12 V source drives 2 A through a resistor. Its resistance is: A. 10 Ω B. 6 Ω C. 14 Ω D. 24 Ω Answer Correct: B. 6 Ω Explanation: R = V/I = 12/2 = 6 Ω.
Key Concept / Clinical Relevance: Ohm’s law
Moderate Clinical / Scenario
Q23. An ECG records voltage differences at the body surface. If electrode contact resistance rises markedly, the tracing is most likely to show: A. Improved signal quality B. Higher cardiac output C. More noise/artifact D. Faster conduction velocity Answer Correct: C. More noise/artifact Explanation: Poor electrode contact raises impedance and increases susceptibility to noise and artifact.
Key Concept / Clinical Relevance: Biomedical electrical measurement
Moderate
Q24. A capacitor stores energy primarily in its: A. Magnetic field B. Mechanical motion C. Mass D. Electric field Answer Correct: D. Electric field Explanation: Energy in a capacitor is stored in the electric field between conductors.
Key Concept / Clinical Relevance: Capacitance
Moderate
Q25. The magnetic force on a stationary electric charge is: A. Zero B. Maximum C. qE D. Always centripetal Answer Correct: A. Zero Explanation: Magnetic force q(v × B) is zero when v = 0.
Key Concept / Clinical Relevance: Magnetism
Moderate
Q26. Faraday’s law relates induced emf to the rate of change of: A. Electric resistance B. Magnetic flux C. Mass D. Temperature Answer Correct: B. Magnetic flux Explanation: An emf is induced when magnetic flux through a circuit changes.
Key Concept / Clinical Relevance: Electromagnetic induction
Moderate
Q27. The rms voltage of a sinusoidal AC supply with peak voltage V₀ is: A. V₀ B. V₀/2 C. V₀/√2 D. √2V₀ Answer Correct: C. V₀/√2 Explanation: For a sinusoid, Vrms = Vpeak/√2.
Key Concept / Clinical Relevance: Alternating current
Moderate Clinical / Scenario
Q28. A defibrillator stores electrical energy before discharge. The component chiefly responsible is a: A. Transformer only B. Diode only C. Resistor D. Capacitor Answer Correct: D. Capacitor Explanation: A charged capacitor can rapidly release stored electrical energy during defibrillation.
Key Concept / Clinical Relevance: Defibrillator physics
Moderate
Q29. Sound intensity is proportional to the square of the wave’s: A. Amplitude B. Frequency only C. Wavelength only D. Period Answer Correct: A. Amplitude Explanation: For a given medium, intensity is proportional to amplitude squared.
Key Concept / Clinical Relevance: Wave intensity
Moderate
Q30. Doppler frequency shift is produced primarily by: A. Diffraction only B. Change in source–observer relative motion C. Total internal reflection D. Polarisation Answer Correct: B. Change in source–observer relative motion Explanation: Relative motion changes the observed frequency.
Key Concept / Clinical Relevance: Doppler effect
Moderate
Q31. The refractive index n of a medium is defined as: A. v/c B. cv C. c/v D. c+v Answer Correct: C. c/v Explanation: n = speed of light in vacuum divided by speed in the medium.
Key Concept / Clinical Relevance: Refraction
Moderate
Q32. A lens of focal length +0.5 m has optical power: A. +0.5 D B. −2 D C. +5 D D. +2 D Answer Correct: D. +2 D Explanation: P = 1/f(m) = 1/0.5 = +2 D.
Key Concept / Clinical Relevance: Lens power
Moderate Clinical / Scenario
Q33. A myopic eye is commonly corrected using a: A. Diverging lens B. Converging lens C. Cylindrical lens in every case D. Plane mirror Answer Correct: A. Diverging lens Explanation: A concave/diverging lens shifts the far-point image onto the retina.
Key Concept / Clinical Relevance: Optics of refractive error
Moderate
Q34. Total internal reflection requires light to travel: A. From lower to higher refractive index at any angle B. From higher to lower refractive index above the critical angle C. Only through vacuum D. Perpendicular to every interface Answer Correct: B. From higher to lower refractive index above the critical angle Explanation: TIR occurs from optically denser to rarer medium when incidence exceeds the critical angle.
Key Concept / Clinical Relevance: Fibre optics
Moderate
Q35. The resolving power of an optical system generally improves when wavelength: A. Increases B. Equals zero only C. Decreases D. Does not matter Answer Correct: C. Decreases Explanation: Diffraction-limited resolution improves at shorter wavelength.
Key Concept / Clinical Relevance: Optical resolution
Moderate
Q36. In the photoelectric effect, increasing light frequency above threshold primarily increases the emitted electron’s maximum: A. Number only B. Mass C. Charge D. Kinetic energy Answer Correct: D. Kinetic energy Explanation: Kmax = hf − work function.
Key Concept / Clinical Relevance: Photoelectric effect
Moderate
Q37. The energy of a photon is: A. hc/λ B. hλ/c C. cλ/h D. h/(cλ) Answer Correct: A. hc/λ Explanation: Photon energy E = hf = hc/λ.
Key Concept / Clinical Relevance: Quantum physics
Moderate Clinical / Scenario
Q38. A radiograph is made with a higher tube voltage (kVp). The X-ray beam generally becomes: A. Less penetrating B. More penetrating C. Non-ionising D. Monochromatic Answer Correct: B. More penetrating Explanation: Higher kVp increases photon energies and beam penetrability.
Key Concept / Clinical Relevance: X-ray physics
Moderate
Q39. Half-life is the time required for the number of undecayed radioactive nuclei to fall to: A. 75% B. 25% C. 50% D. 10% Answer Correct: C. 50% Explanation: By definition, one half-life reduces the undecayed population to one-half.
Key Concept / Clinical Relevance: Radioactivity
Moderate
Q40. Which radiation has the greatest mass among these? A. Gamma ray B. X-ray C. Beta particle D. Alpha particle Answer Correct: D. Alpha particle Explanation: An alpha particle is a helium nucleus with two protons and two neutrons.
Key Concept / Clinical Relevance: Nuclear radiation
Moderate
Q41. The SI unit of absorbed radiation dose is: A. Gray B. Sievert C. Becquerel D. Coulomb Answer Correct: A. Gray Explanation: The gray is one joule of ionising radiation energy absorbed per kilogram.
Key Concept / Clinical Relevance: Radiation dosimetry
Moderate Clinical / Scenario
Q42. During diagnostic ultrasound, a strong echo occurs at a tissue boundary mainly when there is a large difference in: A. Electric charge B. Acoustic impedance C. Radioactivity D. Temperature Answer Correct: B. Acoustic impedance Explanation: Reflection increases with acoustic impedance mismatch across an interface.
Key Concept / Clinical Relevance: Ultrasound physics
Moderate
Q43. Increasing ultrasound frequency generally produces: A. Worse resolution and more penetration B. No change in resolution C. Better resolution but less penetration D. Infinite penetration Answer Correct: C. Better resolution but less penetration Explanation: Higher frequency shortens wavelength, improving resolution but increasing attenuation.
Key Concept / Clinical Relevance: Ultrasound trade-off
Moderate
Q44. In pulse oximetry, oxygen saturation is estimated using differential absorption of approximately: A. Ultraviolet and X-rays B. Gamma and radio waves C. Green light only D. Red and infrared light Answer Correct: D. Red and infrared light Explanation: Oxy- and deoxyhaemoglobin absorb red and infrared wavelengths differently.
Key Concept / Clinical Relevance: Pulse oximetry
Moderate
Q45. MRI primarily detects signals from nuclei with magnetic moments, clinically dominated by: A. Hydrogen protons B. Calcium ions C. Electrons in iron D. Carbon dioxide molecules Answer Correct: A. Hydrogen protons Explanation: Hydrogen is abundant in water and fat and has a strong MR signal.
Key Concept / Clinical Relevance: MRI fundamentals
Moderate Clinical / Scenario
Q46. A patient moves during an MRI acquisition. The most direct image consequence is: A. Ionising radiation burn B. Motion artifact/ghosting C. Higher CT number D. Doppler aliasing Answer Correct: B. Motion artifact/ghosting Explanation: Motion during spatial encoding produces misregistration and ghosting artifacts.
Key Concept / Clinical Relevance: MRI artifacts
Moderate
Q47. CT attenuation is commonly expressed using: A. Dioptres B. Decibels C. Hounsfield units D. Teslas Answer Correct: C. Hounsfield units Explanation: CT numbers are reported in Hounsfield units relative to water.
Key Concept / Clinical Relevance: CT physics
Moderate
Q48. PET imaging detects pairs of photons produced after: A. Alpha decay B. Nuclear fission C. Ultrasound reflection D. Positron–electron annihilation Answer Correct: D. Positron–electron annihilation Explanation: Annihilation produces two approximately 511-keV photons emitted nearly opposite each other.
Key Concept / Clinical Relevance: PET physics
Moderate Clinical / Scenario
Q49. A pulse oximeter gives an unexpectedly low reading in a patient with cold, poorly perfused fingers. The most relevant physical limitation is: A. Weak pulsatile optical signal B. Excess X-ray attenuation C. High acoustic impedance D. Nuclear spin saturation Answer Correct: A. Weak pulsatile optical signal Explanation: Low peripheral perfusion reduces the pulsatile arterial component required for reliable photoplethysmography.
Key Concept / Clinical Relevance: Pulse oximetry limitations
Moderate
Q50. For laminar blood flow, halving vessel radius while all else remains constant changes flow to approximately: A. 1/2 B. 1/16 C. 1/4 D. 1/8 Answer Correct: B. 1/16 Explanation: Poiseuille’s law gives Q ∝ r⁴; (1/2)⁴ = 1/16.
Key Concept / Clinical Relevance: Hemodynamics
Very Difficult
Q51. A projectile is launched at speed u at 45° on level ground without air resistance. Its range is: A. u²/2g B. 2u²/g C. u²/g D. ug Answer Correct: C. u²/g Explanation: R = u² sin2θ/g; at 45°, sin90° = 1.
Key Concept / Clinical Relevance: Projectile motion
Very Difficult Clinical / Scenario
Q52. A 70 kg patient lies on a mattress. If the effective contact area doubles while weight is unchanged, average interface pressure becomes: A. Twice B. Four times C. Unchanged D. Half Answer Correct: D. Half Explanation: Pressure = force/area, so doubling area halves average pressure.
Key Concept / Clinical Relevance: Pressure injury biomechanics
Very Difficult
Q53. For a rigid body with moment of inertia I and angular speed ω, rotational kinetic energy is: A. ½Iω² B. Iω C. I²ω/2 D. ½I²ω Answer Correct: A. ½Iω² Explanation: Rotational kinetic energy is ½Iω².
Key Concept / Clinical Relevance: Rotational dynamics
Very Difficult Clinical / Scenario
Q54. Blood flows through a stenosis whose radius is 60% of the original. Under ideal Poiseuille conditions and unchanged ΔP, flow becomes approximately: A. 36% B. 13% C. 21.6% D. 60% Answer Correct: B. 13% Explanation: Q scales as r⁴; 0.6⁴ = 0.1296, about 13%.
Key Concept / Clinical Relevance: Stenosis and Poiseuille law
Very Difficult
Q55. For steady incompressible flow, the continuity equation implies that when cross-sectional area decreases, mean velocity: A. Decreases proportionally B. Remains fixed C. Increases D. Becomes zero Answer Correct: C. Increases Explanation: A₁v₁ = A₂v₂, so velocity rises as area falls.
Key Concept / Clinical Relevance: Continuity equation
Very Difficult
Q56. Bernoulli’s principle predicts that, at the same height in ideal streamline flow, a region of higher fluid velocity has: A. Higher static pressure B. Identical pressure always C. Zero kinetic energy D. Lower static pressure Answer Correct: D. Lower static pressure Explanation: Along a streamline, increased kinetic-energy density is associated with reduced static pressure.
Key Concept / Clinical Relevance: Bernoulli principle
Very Difficult Clinical / Scenario
Q57. Across a severe arterial stenosis, Doppler velocity rises from 1 to 4 m/s. Using the simplified Bernoulli relation ΔP ≈ 4v², the estimated gradient is: A. 64 mmHg B. 16 mmHg C. 32 mmHg D. 80 mmHg Answer Correct: A. 64 mmHg Explanation: At v = 4 m/s, ΔP ≈ 4 × 16 = 64 mmHg.
Key Concept / Clinical Relevance: Doppler haemodynamics
Very Difficult
Q58. Laplace’s law for a spherical interface gives pressure difference ΔP proportional to: A. Tr B. T/r C. r/T D. 1/(Tr) Answer Correct: B. T/r Explanation: For a sphere ΔP = 2T/r.
Key Concept / Clinical Relevance: Laplace law
Very Difficult
Q59. Two alveoli have equal surface tension but radii r and 2r. Without surfactant, the smaller alveolus has internal pressure: A. Half as large B. The same C. Twice as large D. Four times as large Answer Correct: C. Twice as large Explanation: For an alveolus approximated as a sphere, P ∝ 1/r.
Key Concept / Clinical Relevance: Alveolar stability
Very Difficult Clinical / Scenario
Q60. Pulmonary surfactant particularly stabilises small alveoli because it: A. Raises surface tension most in small alveoli B. Eliminates gas pressure C. Makes air incompressible D. Lowers surface tension, especially as alveoli become smaller Answer Correct: D. Lowers surface tension, especially as alveoli become smaller Explanation: Concentrated surfactant at low lung volumes lowers surface tension and reduces collapse tendency.
Key Concept / Clinical Relevance: Surfactant physics
Very Difficult
Q61. For a gas mixture, Dalton’s law states total pressure equals: A. Sum of partial pressures B. Product of partial pressures C. Mean molecular weight D. Osmotic pressure Answer Correct: A. Sum of partial pressures Explanation: The total pressure of an ideal gas mixture is the sum of component partial pressures.
Key Concept / Clinical Relevance: Partial pressures
Very Difficult
Q62. At constant temperature, compressing an ideal gas to half its volume changes pressure to: A. Half B. Double C. Four times D. Unchanged Answer Correct: B. Double Explanation: Boyle’s law gives P₁V₁=P₂V₂.
Key Concept / Clinical Relevance: Gas compression
Very Difficult Clinical / Scenario
Q63. During positive-pressure ventilation, increasing tidal volume without changing airway resistance most directly increases the pressure needed to overcome: A. Electrical impedance B. Magnetic flux C. Elastic load D. Optical attenuation Answer Correct: C. Elastic load Explanation: Greater volume displacement increases elastic recoil pressure according to compliance.
Key Concept / Clinical Relevance: Ventilator mechanics
Very Difficult
Q64. If lung compliance is 40 mL/cmH₂O and a 400 mL tidal volume is delivered quasi-statically, the elastic pressure change is approximately: A. 5 cmH₂O B. 16 cmH₂O C. 40 cmH₂O D. 10 cmH₂O Answer Correct: D. 10 cmH₂O Explanation: ΔP = ΔV/C = 400/40 = 10 cmH₂O.
Key Concept / Clinical Relevance: Compliance
Very Difficult
Q65. For diffusion across a membrane, Fick’s law predicts transfer rate increases with: A. Surface area B. Membrane thickness C. Inverse concentration gradient D. Molecular size alone Answer Correct: A. Surface area Explanation: Diffusion rate is proportional to area and gradient and inversely proportional to thickness.
Key Concept / Clinical Relevance: Fick’s law
Very Difficult Clinical / Scenario
Q66. A patient develops pulmonary edema that doubles effective diffusion distance. If all other factors remain constant, gas diffusion rate is expected to: A. Double B. Halve C. Quadruple D. Remain unchanged Answer Correct: B. Halve Explanation: Fick’s law makes diffusion inversely proportional to membrane thickness.
Key Concept / Clinical Relevance: Gas diffusion
Very Difficult
Q67. A capacitor of 100 μF charged to 200 V stores approximately: A. 0.2 J B. 1 J C. 2 J D. 20 J Answer Correct: C. 2 J Explanation: E = ½CV² = 0.5 × 100×10⁻⁶ × 40000 = 2 J.
Key Concept / Clinical Relevance: Capacitor energy
Very Difficult
Q68. In an RC circuit, the time constant is: A. R/C B. 1/RC C. R+C D. RC Answer Correct: D. RC Explanation: The characteristic charging/discharging time constant is τ = RC.
Key Concept / Clinical Relevance: RC circuits
Very Difficult Clinical / Scenario
Q69. A defibrillator with capacitance 200 μF is charged to 1000 V. Stored energy is: A. 100 J B. 10 J C. 50 J D. 200 J Answer Correct: A. 100 J Explanation: E = ½CV² = 0.5 × 200×10⁻⁶ × 10⁶ = 100 J.
Key Concept / Clinical Relevance: Defibrillator energy
Very Difficult
Q70. The impedance of an ideal capacitor in AC has magnitude: A. 2πfC B. 1/(2πfC) C. 2πf/C D. C/(2πf) Answer Correct: B. 1/(2πfC) Explanation: Capacitive reactance Xc = 1/(2πfC).
Key Concept / Clinical Relevance: AC impedance
Very Difficult
Q71. A transformer ideally changes voltage according to the ratio of: A. Resistances B. Frequencies C. Turns in secondary to primary D. Core masses Answer Correct: C. Turns in secondary to primary Explanation: Vs/Vp = Ns/Np for an ideal transformer.
Key Concept / Clinical Relevance: Transformers
Very Difficult Clinical / Scenario
Q72. An isolation transformer in medical equipment principally reduces risk by: A. Increasing radiation dose B. Amplifying ECG voltage C. Creating DC from AC D. Breaking direct conductive connection to mains Answer Correct: D. Breaking direct conductive connection to mains Explanation: Galvanic isolation limits hazardous current paths between mains and patient circuits.
Key Concept / Clinical Relevance: Electrical safety
Very Difficult
Q73. For a charged particle moving perpendicular to a uniform magnetic field, the magnetic force does: A. No work B. Positive work continuously C. Negative work continuously D. Work only at low speed Answer Correct: A. No work Explanation: Magnetic force is perpendicular to velocity, changing direction but not speed.
Key Concept / Clinical Relevance: Lorentz force
Very Difficult
Q74. Lenz’s law determines the induced current direction so that its magnetic effect: A. Enhances the flux change B. Opposes the flux change C. Is unrelated to flux D. Always points north Answer Correct: B. Opposes the flux change Explanation: The induced response opposes the change that produced it.
Key Concept / Clinical Relevance: Lenz’s law
Very Difficult
Q75. In MRI, the Larmor angular frequency ω₀ is proportional to: A. 1/B₀ B. B₀² only C. B₀ D. Gradient slew rate only Answer Correct: C. B₀ Explanation: ω₀ = γB₀.
Key Concept / Clinical Relevance: Larmor precession
Very Difficult Clinical / Scenario
Q76. Moving from a 1.5 T to a 3 T MRI scanner approximately does what to proton Larmor frequency? A. Halves it B. Quadruples it C. Leaves it unchanged D. Doubles it Answer Correct: D. Doubles it Explanation: Larmor frequency is directly proportional to static field strength.
Key Concept / Clinical Relevance: MRI field strength
Very Difficult
Q77. T1 relaxation describes recovery of: A. Longitudinal magnetisation B. Transverse coherence C. Gradient strength D. X-ray attenuation Answer Correct: A. Longitudinal magnetisation Explanation: T1 is spin-lattice recovery of longitudinal magnetisation.
Key Concept / Clinical Relevance: MRI relaxation
Very Difficult
Q78. T2 relaxation describes decay of: A. Longitudinal magnetisation only B. Transverse magnetisation due to spin-spin dephasing C. Proton number D. Static magnetic field Answer Correct: B. Transverse magnetisation due to spin-spin dephasing Explanation: T2 is the time constant of transverse spin-spin dephasing.
Key Concept / Clinical Relevance: MRI relaxation
Very Difficult Clinical / Scenario
Q79. A spin-echo sequence uses a 180° pulse primarily to reduce signal loss from: A. True T2 interactions B. Proton density C. Static field inhomogeneity dephasing D. Longitudinal recovery Answer Correct: C. Static field inhomogeneity dephasing Explanation: The 180° refocusing pulse reverses dephasing from static field variations, yielding T2 rather than T2*.
Key Concept / Clinical Relevance: MRI spin echo
Very Difficult
Q80. In diagnostic ultrasound, axial resolution is improved most directly by: A. Longer spatial pulse length B. Lower sound speed C. Higher beam width D. Shorter spatial pulse length Answer Correct: D. Shorter spatial pulse length Explanation: Axial resolution is approximately half the spatial pulse length.
Key Concept / Clinical Relevance: Ultrasound resolution
Very Difficult
Q81. Doppler aliasing in pulsed-wave ultrasound occurs when Doppler shift exceeds: A. Nyquist limit B. The acoustic impedance C. Attenuation coefficient D. Critical angle Answer Correct: A. Nyquist limit Explanation: The maximum unambiguous sampled frequency is half the pulse repetition frequency.
Key Concept / Clinical Relevance: Doppler aliasing
Very Difficult Clinical / Scenario
Q82. A Doppler study shows aliasing at high blood velocity. Which change can raise the Nyquist limit? A. Decrease PRF B. Increase PRF C. Increase wavelength only D. Set Doppler angle to 90° Answer Correct: B. Increase PRF Explanation: Nyquist limit = PRF/2; increasing PRF increases the measurable shift before aliasing.
Key Concept / Clinical Relevance: Pulsed Doppler
Very Difficult
Q83. For Doppler ultrasound, measured frequency shift approaches zero when the beam-flow angle approaches: A. 0° B. 30° C. 90° D. 60° Answer Correct: C. 90° Explanation: Doppler shift contains cosθ; cos90° = 0.
Key Concept / Clinical Relevance: Doppler angle
Very Difficult
Q84. Acoustic impedance Z is the product of tissue density and: A. Frequency B. Wavelength squared C. Attenuation only D. Sound speed Answer Correct: D. Sound speed Explanation: Z = ρc.
Key Concept / Clinical Relevance: Acoustic impedance
Very Difficult Clinical / Scenario
Q85. At a soft-tissue–air interface, ultrasound transmission is poor chiefly because of: A. Large acoustic impedance mismatch B. Minimal impedance mismatch C. Identical sound speeds D. No reflection Answer Correct: A. Large acoustic impedance mismatch Explanation: The large impedance difference causes strong reflection, which is why coupling gel is used.
Key Concept / Clinical Relevance: Ultrasound coupling
Very Difficult
Q86. The minimum resolvable separation of two point objects due to diffraction is approximately proportional to: A. NA/λ B. λ/NA C. λ×NA² D. 1/(λNA) Answer Correct: B. λ/NA Explanation: Resolution limit scales with wavelength divided by numerical aperture.
Key Concept / Clinical Relevance: Diffraction limit
Very Difficult
Q87. In optical fibres, increasing the numerical aperture generally increases the: A. Critical wavelength only B. Photon energy C. Acceptance angle D. Speed of light in vacuum Answer Correct: C. Acceptance angle Explanation: Higher numerical aperture permits a wider cone of accepted rays.
Key Concept / Clinical Relevance: Fibre optics
Very Difficult Clinical / Scenario
Q88. An endoscope uses optical fibres to transmit light around bends primarily by: A. Compton scattering B. Photoelectric absorption C. Nuclear resonance D. Total internal reflection Answer Correct: D. Total internal reflection Explanation: Light remains guided within the core through repeated total internal reflection.
Key Concept / Clinical Relevance: Endoscopy optics
Very Difficult
Q89. For X-ray photons in diagnostic imaging, photoelectric absorption probability increases strongly with: A. Higher atomic number and lower photon energy B. Lower atomic number C. Higher photon energy only D. Lower density only Answer Correct: A. Higher atomic number and lower photon energy Explanation: Photoelectric interaction rises steeply with atomic number and falls with photon energy.
Key Concept / Clinical Relevance: X-ray interactions
Very Difficult
Q90. Compton scattering depends primarily on the material’s: A. Atomic number to the fourth power B. Electron density C. Magnetic susceptibility only D. Optical refractive index Answer Correct: B. Electron density Explanation: In the diagnostic range, Compton probability is mainly related to electron density.
Key Concept / Clinical Relevance: Compton effect
Very Difficult Clinical / Scenario
Q91. After iodinated contrast is administered for CT, vessels appear more attenuating chiefly because iodine: A. Eliminates Compton scatter B. Produces ultrasound C. Has a relatively high atomic number D. Lowers photon energy to zero Answer Correct: C. Has a relatively high atomic number Explanation: Iodine’s high atomic number increases X-ray attenuation, especially photoelectric absorption.
Key Concept / Clinical Relevance: CT contrast physics
Very Difficult
Q92. The Hounsfield unit of water is defined as approximately: A. −1000 B. −100 C. +1000 D. 0 Answer Correct: D. 0 Explanation: Water is the reference at 0 HU; air is about −1000 HU.
Key Concept / Clinical Relevance: CT numbers
Very Difficult
Q93. If CT slice thickness is reduced while other factors are unchanged, partial-volume averaging generally: A. Decreases B. Increases C. Becomes infinite D. Is unrelated Answer Correct: A. Decreases Explanation: Thinner slices contain fewer mixed tissues and reduce partial-volume effects.
Key Concept / Clinical Relevance: CT spatial resolution
Very Difficult Clinical / Scenario
Q94. A small lesion adjacent to dense bone is obscured on thick CT slices but becomes visible on thinner reconstructions. The key improvement is reduced: A. Larmor frequency B. Partial-volume averaging C. Radioactive decay D. Doppler shift Answer Correct: B. Partial-volume averaging Explanation: Thinner slices reduce averaging of different tissues within a voxel.
Key Concept / Clinical Relevance: CT partial-volume effect
Very Difficult
Q95. Radioactive activity measured in becquerels represents: A. Absorbed joules/kg B. Biological weighting C. Disintegrations per second D. Photon energy in eV Answer Correct: C. Disintegrations per second Explanation: 1 Bq equals one nuclear transformation per second.
Key Concept / Clinical Relevance: Radioactivity units
Very Difficult Clinical / Scenario
Q96. A staff member steps from 1 m to 2 m from an approximately point-like radiation source. Ignoring scatter, exposure rate becomes about: A. Double B. Half C. One-eighth D. One-quarter Answer Correct: D. One-quarter Explanation: Inverse-square behavior gives I₂/I₁=(1/2)²=1/4.
Key Concept / Clinical Relevance: Radiation safety
Very Difficult Clinical / Scenario
Q97. A PET tracer emits a positron. Before annihilation, positron travel in tissue contributes chiefly to: A. A limit on spatial resolution B. Improved spatial resolution C. Higher MRI signal D. Doppler aliasing Answer Correct: A. A limit on spatial resolution Explanation: Positron range separates decay from annihilation location and blurs spatial localisation.
Key Concept / Clinical Relevance: PET resolution
Very Difficult Clinical / Scenario
Q98. A pulse oximeter may display a misleading saturation in carbon monoxide poisoning because conventional two-wavelength devices cannot reliably distinguish: A. Water from plasma B. Oxyhaemoglobin from carboxyhaemoglobin C. Sodium from potassium D. Venous from arterial pressure Answer Correct: B. Oxyhaemoglobin from carboxyhaemoglobin Explanation: Standard pulse oximetry has limited spectral discrimination and may count carboxyhaemoglobin as oxyhaemoglobin.
Key Concept / Clinical Relevance: Optical spectroscopy limitations
Very Difficult Clinical / Scenario
Q99. A mechanically ventilated patient has a capnogram with a sloping expiratory plateau. From a physical measurement standpoint, this most directly reflects: A. X-ray attenuation B. Electrical capacitance C. Nonuniform emptying and gas mixing D. Magnetic resonance Answer Correct: C. Nonuniform emptying and gas mixing Explanation: Unequal time constants and heterogeneous exhalation produce a rising alveolar plateau.
Key Concept / Clinical Relevance: Capnography waveform physics
Very Difficult Clinical / Scenario
Q100. A patient with marked polycythaemia has increased blood viscosity. Under otherwise comparable conditions, vascular resistance tends to: A. Decrease B. Become zero C. Be independent of viscosity D. Increase Answer Correct: D. Increase Explanation: Laminar resistance is directly proportional to viscosity.
Key Concept / Clinical Relevance: Blood viscosity and resistance